from sequtils import anyIt

template `?:`*(a, b: string): string =
  if len(a) > 0: a else: b

template `?:`*(a: object, b: string): string =
  if a: $a else: b

template `?:`*(a: ref, b): auto =
  if a != nil: a else: b

template `?:`*(a, b: object): object =
  if a: a else: b

template `?:`*(a, b): auto =
  if a: a else: b

template `?.`*(a: ref, b: untyped): auto =
  if a != nil: a.b else: nil

proc sameContents*[T](a1, a2: openArray[T]): bool =
  # Answers the question: do these two arrays contain the same contents,
  # regardless of their order?
  if a1.len != a2.len: return false
  for a in a1:
    if not a2.anyIt(a == it): return false
  return true

template indexOf*(s, pred: untyped): int =
  var foundIdx = -1
  var idx = 0
  for it {.inject.} in items(s):
    if pred:
      foundIdx = idx
      break
    idx += 1
  foundIdx

template doWhile*(a, b: untyped): untyped =
  b
  while a:
    b